CBSE • Class 10Science • Chapter 10

The Human Eye and the Colourful WorldNCERT Solutions, AI Tutor & Practice

The human eye, defects of vision and their correction, dispersion of light through a prism, atmospheric refraction and scattering of light.

Aligned to the latest NCERT 2024-25 edition • 1 exercises covered • Free plan, no credit card

What you will learn

  • Describe the structure and working of the human eye
  • Explain myopia, hypermetropia and presbyopia and their correction
  • Explain dispersion, recombination and the formation of a rainbow
  • Use scattering to explain the blue sky and red sunset

Key concepts in this chapter

AccommodationMyopiaHypermetropiaPresbyopiaDispersionTyndall effectScattering

Frequently asked NCERT questions in this chapter

  1. What is the far point and near point of the human eye?
  2. Why do stars twinkle but planets do not?
  3. Why is the colour of the sky blue?

Step-by-step NCERT solutions

12 solved questions • Each solution includes a Socratic hint, full working and a common-mistake callout • Last reviewed 2026-09-03

Q1 • 2 marks

What is meant by the power of accommodation of the human eye? Which part of the eye is responsible for it?
Hint (Socratic — try this first)
How does the eye manage to see both a distant tree and a nearby book clearly without moving?
Step-by-step solution

Power of accommodation is the ability of the eye to adjust the focal length of its lens so that objects at different distances form sharp images on the retina.

How it works:

  • The ciliary muscles control the curvature (and hence the focal length) of the crystalline eye lens.
  • When viewing distant objects, the ciliary muscles relax, the lens becomes thin, its focal length increases.
  • When viewing nearby objects, the ciliary muscles contract, the lens becomes thick, its focal length decreases.

Thus the eye lens (with the help of ciliary muscles) is responsible for accommodation.

Common mistake:
Students often say the retina or cornea changes shape, but it is the flexible eye lens (adjusted by ciliary muscles) that changes focal length.
Open this question in the AI tutor →

Q2 • 2 marks

Define the near point and far point of a normal human eye. What is the least distance of distinct vision?
Hint (Socratic — try this first)
What is the closest and farthest a healthy eye can focus comfortably?
Step-by-step solution

Far point: The farthest point up to which the eye can see objects clearly. For a normal eye it is at infinity.

Near point: The closest point at which the eye can see an object clearly and comfortably without strain. For a normal adult eye it is about 25 cm.

Least distance of distinct vision: The minimum distance at which an object can be seen most clearly without strain. This distance equals the near point, i.e. about 25 cm for a normal eye.

Common mistake:
Writing the near point as 25 m instead of 25 cm, or confusing the least distance of distinct vision with the far point.
Open this question in the AI tutor →

Q3 • 3 marks

A person suffering from myopia cannot see objects clearly beyond 1.5 m. Find the nature and power of the lens required to correct this defect.
Hint (Socratic — try this first)
For myopia, where should a distant object's image be formed so the eye can then see it — at the eye's own far point?
Step-by-step solution

Defect: Myopia (short-sightedness) is corrected using a concave (diverging) lens.

The lens must form the image of a very distant object (at infinity) at the person's far point, so that the eye can see it.

  • Object distance: u=u = -\infty
  • Image distance: v=1.5 mv = -1.5\ \text{m} (far point, on same side as object)

Using the lens formula: 1f=1v1u=11.51=11.5\frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{-1.5} - \frac{1}{-\infty} = -\frac{1}{1.5} f=1.5 mf = -1.5\ \text{m}

Power: P=1f(in m)=11.5=0.67 DP = \frac{1}{f\,(\text{in m})} = \frac{1}{-1.5} = -0.67\ \text{D}

A concave lens of power 0.67 D-0.67\ \text{D} is required.

Common mistake:
Forgetting the negative sign for image distance/power, or using distance in cm without converting to metres when calculating power.
Open this question in the AI tutor →

Q4 • 3 marks

A person with hypermetropia has a near point of 1 m. Calculate the power of the corrective lens needed to read a book held at the normal near point of 25 cm.
Hint (Socratic — try this first)
The lens should make an object at 25 cm appear to be located at the eye's actual near point of 1 m.
Step-by-step solution

Defect: Hypermetropia (long-sightedness) is corrected using a convex (converging) lens.

The lens must form the image of an object placed at 25 cm at the person's near point (1 m), so the eye can see it.

  • Object distance: u=25 cm=0.25 mu = -25\ \text{cm} = -0.25\ \text{m}
  • Image distance: v=100 cm=1 mv = -100\ \text{cm} = -1\ \text{m} (near point, virtual, same side)

Using the lens formula: 1f=1v1u=1110.25=1+4=3\frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{-1} - \frac{1}{-0.25} = -1 + 4 = 3 f=13 m=+0.33 mf = \frac{1}{3}\ \text{m} = +0.33\ \text{m}

Power: P=1f=+3 DP = \frac{1}{f} = +3\ \text{D}

A convex lens of power +3 D+3\ \text{D} is required.

Common mistake:
Mixing up the signs of u and v, or forgetting that both the object and image distances are negative (measured against the direction of incident light).
Open this question in the AI tutor →

Q5 • 3 marks

Why do stars appear to twinkle while planets do not?
Hint (Socratic — try this first)
Does a point-like source of light and an extended source behave the same way when light passes through the wobbling atmosphere?
Step-by-step solution

Twinkling of stars is caused by atmospheric refraction of starlight.

Understanding:

  • Stars are extremely far away, so they act as point sources of light.
  • As starlight enters the Earth's atmosphere, it is refracted continuously through layers of air of changing density (due to temperature variations and air movement).
  • The apparent position of the star keeps shifting slightly, and the amount of light entering the eye keeps changing — sometimes brighter, sometimes fainter. This is seen as twinkling.

Why planets don't twinkle:

  • Planets are much closer, so they appear as extended sources — a collection of many point sources.
  • The variations in light from these individual points average out, cancelling the flickering effect.

Hence planets do not appear to twinkle.

Common mistake:
Attributing twinkling to the star's own brightness changing, rather than to atmospheric refraction of light from a point source.
Open this question in the AI tutor →

Q6 • 3 marks

Explain why the Sun appears reddish at sunrise and sunset but white during the day (at noon).
Hint (Socratic — try this first)
Which colours of light get scattered away most when sunlight travels through a long thickness of atmosphere near the horizon?
Step-by-step solution

This is explained by the scattering of light by air molecules (Tyndall/Rayleigh scattering).

Key principle: Scattering is stronger for shorter wavelengths (blue/violet) than for longer wavelengths (red).

At sunrise/sunset:

  • Sunlight travels through a greater thickness of atmosphere to reach us (it enters at a low angle near the horizon).
  • Most of the shorter-wavelength blue light is scattered away during this long path.
  • Mainly the longer-wavelength red light reaches our eyes, so the Sun appears reddish.

At noon:

  • The Sun is overhead, so light passes through the least thickness of atmosphere.
  • Comparatively little light is scattered, so the Sun appears nearly white.
Common mistake:
Claiming the Sun physically becomes red or that clouds cause the colour, instead of explaining that blue light is scattered out over the longer atmospheric path.
Open this question in the AI tutor →

Q7 • 3 marks

What is meant by dispersion of white light? Describe how a glass prism produces a spectrum.
Hint (Socratic — try this first)
Do all colours in white light bend by the same amount when passing through glass?
Step-by-step solution

Dispersion of light: The splitting of white light into its component colours (VIBGYOR) when it passes through a medium such as a glass prism.

How a prism produces a spectrum:

  • White light is a mixture of seven colours, each with a different wavelength.
  • Different colours travel at different speeds in glass, so they bend by different amounts (they have different refractive indices in glass).
  • Violet (shortest wavelength) bends the most; red (longest wavelength) bends the least.
  • Because of this unequal bending, the colours separate and emerge in a band called the spectrum.

The sequence of colours obtained is Violet, Indigo, Blue, Green, Yellow, Orange, Red (VIBGYOR).

Common mistake:
Stating that red bends most because it 'travels farthest' — in fact violet is deviated the most and red the least.
Open this question in the AI tutor →

Q8 • 3 marks

How is a rainbow formed in the sky after rain?
Hint (Socratic — try this first)
What role do tiny water droplets play — do they act like tiny prisms that both refract and reflect sunlight?
Step-by-step solution

A rainbow is a natural spectrum formed by the dispersion of sunlight by tiny water droplets present in the atmosphere after rain.

Formation (step by step):

  1. Sunlight enters a water droplet and gets refracted (bent). During this refraction, dispersion begins as different colours bend differently.
  2. The light is then internally reflected off the back inner surface of the droplet.
  3. The light is refracted again as it leaves the droplet, further separating the colours.

Thus each droplet acts like a tiny prism. The combined effect of millions of droplets produces the coloured arc — a rainbow — with red on the outer edge and violet on the inner edge.

Condition: A rainbow is always seen in the direction opposite to the Sun, with the observer's back to the Sun.

Common mistake:
Forgetting the internal reflection step, or reversing the colour order (violet is on the inside, red on the outside of a primary rainbow).
Open this question in the AI tutor →

Q9 • 3 marks

What is atmospheric refraction? Using this concept, explain the advance sunrise and delayed sunset.
Hint (Socratic — try this first)
Does the density of air (and hence its refractive index) stay the same at all heights above the ground?
Step-by-step solution

Atmospheric refraction: The bending of light as it passes through layers of the Earth's atmosphere that have different densities (and therefore different refractive indices). The air near the surface is denser than the air higher up.

Advance sunrise and delayed sunset:

  • When the Sun is slightly below the horizon, its light travels from the rarer (upper) atmosphere into the denser (lower) atmosphere and is refracted, bending towards the observer.
  • This makes the Sun appear raised above its actual position.
  • Because of this, we can see the Sun about 2 minutes before it actually rises (advance sunrise) and for about 2 minutes after it has actually set (delayed sunset).

Thus the day appears about 4 minutes longer than it actually is due to atmospheric refraction.

Common mistake:
Saying the Sun is physically higher, instead of explaining that refraction makes the apparent position higher than the true position.
Open this question in the AI tutor →

Q10 • 3 marks

Why is the colour of the clear sky blue? Would the sky appear blue if the Earth had no atmosphere?
Hint (Socratic — try this first)
Which colour of sunlight is scattered most by the small molecules of air?
Step-by-step solution

The blue colour of the sky is due to the scattering of sunlight by the tiny molecules of air (Rayleigh scattering).

Explanation:

  • Scattering is much stronger for shorter wavelengths. Blue light (short wavelength) is scattered far more than red light (long wavelength).
  • As sunlight passes through the atmosphere, blue light is scattered in all directions by air molecules.
  • This scattered blue light reaches our eyes from all parts of the sky, so the sky appears blue.

(Violet is scattered even more, but our eyes are more sensitive to blue, and sunlight contains more blue, so we perceive blue.)

Without atmosphere: If the Earth had no atmosphere, there would be no scattering, so the sky would appear dark/black even in daytime, as seen by astronauts in space.

Common mistake:
Thinking the sky is blue because it reflects the colour of the oceans, rather than because of preferential scattering of blue light.
Open this question in the AI tutor →

Q11 • 3 marks

The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to enable him to see very distant objects clearly?
Hint (Socratic — try this first)
The corrective lens must move the image of an object at infinity to the person's far point.
Step-by-step solution

Defect: Myopia — corrected using a concave (diverging) lens.

The lens must form the image of a distant object (at infinity) at the far point of the eye (80 cm).

  • Object distance: u=u = -\infty
  • Image distance: v=80 cm=0.8 mv = -80\ \text{cm} = -0.8\ \text{m}

Lens formula: 1f=1v1u=10.80=1.25\frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{-0.8} - 0 = -1.25 f=0.8 mf = -0.8\ \text{m}

Power: P=1f=10.8=1.25 DP = \frac{1}{f} = \frac{1}{-0.8} = -1.25\ \text{D}

Required: a concave lens of power 1.25 D-1.25\ \text{D} (focal length 80 cm-80\ \text{cm}).

Common mistake:
Giving a positive power or forgetting to convert 80 cm into 0.8 m before computing power.
Open this question in the AI tutor →

Q12 • 3 marks

State the causes of (a) myopia and (b) hypermetropia, and name the type of lens used to correct each.
Hint (Socratic — try this first)
Think about whether the eyeball is too long or too short, and whether the image forms in front of or behind the retina.
Step-by-step solution

(a) Myopia (short-sightedness):

  • The person can see nearby objects clearly but distant objects appear blurred.
  • Causes: (i) excessive curvature of the eye lens (too much converging power), or (ii) the eyeball being too long (elongated).
  • The image of a distant object forms in front of the retina.
  • Correction: a concave (diverging) lens.

(b) Hypermetropia (long-sightedness):

  • The person can see distant objects clearly but nearby objects appear blurred.
  • Causes: (i) the eye lens having too little converging power (focal length too long), or (ii) the eyeball being too short.
  • The image of a nearby object forms behind the retina.
  • Correction: a convex (converging) lens.
Common mistake:
Swapping the eyeball lengths — students often say a short eyeball causes myopia, when in fact a long eyeball causes myopia and a short eyeball causes hypermetropia.
Open this question in the AI tutor →

How to solve The Human Eye and the Colourful World on Mindarc

  1. Watch the chapter overview video. A short animated explainer that maps the chapter to the NCERT textbook layout.
  2. Read the concept summary. Key definitions, formulas and worked examples for each concept.
  3. Solve with Guru AI. Open any exercise question in the dashboard; the Socratic AI tutor walks you through it by asking guiding questions instead of dictating answers.
  4. Take the adaptive practice set. The platform adjusts difficulty based on how you perform and surfaces the concepts you are weakest on.
  5. Track mastery in your parent dashboard. See per-concept progress for The Human Eye and the Colourful World alongside every other chapter.

FAQs about this chapter

Why does the sun appear reddish at sunrise and sunset?+

At sunrise and sunset, sunlight travels a much greater thickness of the atmosphere. Most of the shorter-wavelength blue light is scattered out before reaching the observer, while the longer-wavelength red light continues to reach the eye, making the sun appear reddish.

All Class 10 Science chapters

  1. 1.Chemical Reactions and Equations
  2. 2.Acids, Bases and Salts
  3. 3.Metals and Non-metals
  4. 4.Carbon and its Compounds
  5. 5.Life Processes
  6. 6.Control and Coordination
  7. 7.How do Organisms Reproduce?
  8. 8.Heredity
  9. 9.Light – Reflection and Refraction
  10. 10.The Human Eye and the Colourful World
  11. 11.Electricity
  12. 12.Magnetic Effects of Electric Current
  13. 13.Our Environment

Related chapters

Solve The Human Eye and the Colourful World with AI guidance

Free plan. No credit card. Works on any device.

Start Free