CBSE • Class 9Mathematics • Chapter 2 (Polynomials) • Exercise 2.1

Exercise 2.1: Polynomials — NCERT Solutions

Polynomials in one variable — degree, coefficients and zeros.

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What this exercise covers

Polynomial definitionDegreeZeros

Step-by-step solutions — Exercise 2.1

3 solved questions • Each solution includes a Socratic hint, full working and a common-mistake callout • Last reviewed 2026-09-03

Exercise 2.1 Q1 • 4 marks

Which of the following expressions are polynomials in one variable and which are not? Give reasons: (i) 4x23x+74x^2 - 3x + 7, (ii) y2+2y^2 + \sqrt{2}, (iii) 3t+t23\sqrt{t} + t\sqrt{2}, (iv) x+2xx + \dfrac{2}{x}.
Hint (Socratic — try this first)
In a polynomial, what kind of numbers are allowed as the exponents of the variable?
Step-by-step solution

A polynomial in one variable must have only whole-number exponents of the variable.

(i) 4x23x+74x^2 - 3x + 7: exponents are 2,1,02, 1, 0 — all whole numbers. It is a polynomial.

(ii) y2+2y^2 + \sqrt{2}: exponent of yy is 22; 2\sqrt{2} is just a constant coefficient. It is a polynomial.

(iii) 3t+t2=3t1/2+2t3\sqrt{t} + t\sqrt{2} = 3t^{1/2} + \sqrt{2}\,t: the term 3t1/23t^{1/2} has exponent 12\tfrac12, which is not a whole number. It is not a polynomial.

(iv) x+2x=x+2x1x + \dfrac{2}{x} = x + 2x^{-1}: exponent 1-1 is not a whole number. It is not a polynomial.

Common mistake:
Thinking 2\sqrt{2} as a coefficient makes an expression non-polynomial — it is the exponent of the variable that matters, not irrational coefficients.
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Exercise 2.1 Q2 • 4 marks

Write the coefficient of x2x^2 in each of the following: (i) 5x2+4x5 - x^2 + 4x, (ii) 2x23x\sqrt{2}\,x^2 - 3x, (iii) π2x2+x\dfrac{\pi}{2}x^2 + x, (iv) 3x5\sqrt{3}\,x - 5.
Hint (Socratic — try this first)
What number is multiplied directly by the x2x^2 term in each expression?
Step-by-step solution

The coefficient of x2x^2 is the number multiplying x2x^2.

(i) 5x2+4x5 - x^2 + 4x: the x2x^2 term is x2=1x2-x^2 = -1\cdot x^2, so coefficient =1= -1.

(ii) 2x23x\sqrt{2}\,x^2 - 3x: coefficient =2= \sqrt{2}.

(iii) π2x2+x\dfrac{\pi}{2}x^2 + x: coefficient =π2= \dfrac{\pi}{2}.

(iv) 3x5\sqrt{3}\,x - 5: there is no x2x^2 term, so coefficient =0= 0.

Common mistake:
Forgetting the negative sign (writing 11 instead of 1-1 in part (i)) or overlooking that a missing term has coefficient 00.
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Exercise 2.1 Q3 • 3 marks

Determine the degree of each polynomial: (i) 7x34x2+x97x^3 - 4x^2 + x - 9, (ii) 5y25 - y^2, (iii) 33 (a constant), (iv) x42x2+6x^{4} - 2x^{2} + 6.
Hint (Socratic — try this first)
Which term carries the highest power of the variable?
Step-by-step solution

The degree is the highest power of the variable appearing in the polynomial.

(i) 7x34x2+x97x^3 - 4x^2 + x - 9: highest power is 33, so degree =3= 3.

(ii) 5y25 - y^2: highest power is 22, so degree =2= 2.

(iii) 33: a non-zero constant is written as 3x03x^0, so degree =0= 0.

(iv) x42x2+6x^4 - 2x^2 + 6: highest power is 44, so degree =4= 4.

Common mistake:
Saying the degree of a non-zero constant like 33 is undefined; it is actually 00 (only the zero polynomial has undefined/no degree).
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How to approach Exercise 2.1

  1. Re-read the chapter summary first. Open Polynomials and refresh the key concepts: Polynomial, Degree, Remainder theorem, Factor theorem.
  2. Try each problem yourself before opening the solution. Ten focused minutes per problem usually beats reading two finished solutions.
  3. Use Guru AI for the questions you get stuck on. The Socratic AI tutor walks you through it with hints instead of dictating the answer.
  4. Mark the questions you got wrong and revisit them after 24 hours — the spacing is what locks the method into long-term memory.

All exercises in Polynomials

  1. Exercise 2.1Polynomials in one variable — degree, coefficients and zeros.
  2. Exercise 2.2Zeros of linear and quadratic polynomials — finding roots algebraically.
  3. Exercise 2.3The Remainder Theorem — evaluating remainders without long division.
  4. Exercise 2.4The Factor Theorem — detecting factors (x − a) from functional values.
  5. Exercise 2.5Algebraic identities — expanding and factorising cubic-type expressions.

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