We split the middle term. We need two numbers whose product is 6×(−2)=−12 and whose sum is −1. These numbers are −4 and 3.
6x2−4x+3x−2=0
2x(3x−2)+1(3x−2)=0
(3x−2)(2x+1)=0
Setting each factor to zero:
3x−2=0⇒x=32
2x+1=0⇒x=−21
Thus the roots are x=32 and x=−21.